怎樣畫一個正方體，如下圖？

Question

\documentclass[pstricks,border=10pt]{standalone}
\usepackage{pst-solides3d}
\begin{document}
\psset{viewpoint=120 50 30 rtp2xyz,Decran=50}
\pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
\def\figure#1#2{%
\begin{pspicture}(-3,-3)(3,3)
\psframe[linestyle=none,fillstyle=solid,fillcolor=blue!50](-3,-3)(3,3)
    \psSolid[action=draw**,a=8,object=cube,fillcolor=green!30,ngrid=3,%
    rm=4 40 13 31 53 22,hollow,incolor=pink!50,Rot#2=-#1\space]%
    \end{pspicture}
}
    \multido{\iA=0+5}{72}{\figure{\iA}{X}}
\end{document}

它的立方體內部是空心的。

那麼，如何獲得與下圖類似的輸出呢？

%% 來自赫伯特的評論

\documentclass[pstricks]{standalone}
\usepackage{pst-solides3d}
\begin{document}

\begin{pspicture}(-4.5,-3.5)(6,6)
\psset{Decran=60,viewpoint=80 35 15 rtp2xyz,a=1,lightsrc=80 30 20,}
%   \psSolid[object=grille,base=0 7 0 7,fillcolor=gray!40]%%
%   \psSolid[object=grille,base=0 7 0 7,RotY=90,fillcolor=gray!30](0,0,7)%
%   \psSolid[object=grille,base=0 7 0 7,RotX=-90,fillcolor=gray!20](0,0,7)%
\def\figure#1#2#3{\psSolid[object=cube,fcol=1 (green) 2 (blue) 3 (red) 4 (pink) 5 (orange) 6 (cyan)](#1,#2,#3)}
    \foreach \i in {0.5,1.5,2.5}{\figure{0.5}{\i}{0.5}}
    \foreach \i in {1.5,2.5}{\figure{\i}{.5}{0.5}}
    \figure{1.5}{2.5}{0.5}
    \foreach \i in {1.5,2.5}{\figure{2.5}{\i}{0.5}}
    \foreach \i in {1.5,2.5}{\figure{.5}{.5}{\i}}
    \figure{2.5}{.5}{1.5}
    \figure{.5}{1.5}{2.5}
    \foreach \i in {1.5,2.5}{\figure{\i}{.5}{2.5}}
    \figure{2.5}{1.5}{2.5}
    \foreach \i in {1.5,2.5}{\figure{.5}{2.5}{\i}}
    \figure{1.5}{2.5}{2.5}
    \foreach \i in {1.5,2.5}{\figure{2.5}{2.5}{\i}}
\end{pspicture}
\end{document}

但使用 view=80 135 15 rtp2xyz ，我得到以下結果：

Answer 1

如果你不希望內部也有立方體，很簡單：

\documentclass[pstricks,border=10pt]{standalone}
\usepackage{pst-solides3d}
\begin{document}
\psset{viewpoint=120 60 30 rtp2xyz,Decran=50}
\pstVerb{/Colors [(red)(yellow)(orange)(green)(blue)] def }
\begin{pspicture}(-3,-3)(3,3)
\psSolid[action=draw**,a=8,object=cube,fillcolor=green!30,ngrid=7,%
    rm=  8  12  24  36  40 
        57  61  73  85  89
       106 110 122 134 138
       155 159 171 183 187
       208 212 220 228 232
       269 273 281 289 293,
        hollow,incolor=blue!30]%
\end{pspicture}
\end{document}

作為單一立方體：

\documentclass[pstricks]{standalone}
\usepackage{pst-solides3d}
\def\Figure#1#2#3#4{%
    \psSolid[object=cube,name=c#4,ngrid=1,a=1,
             action=none,fcol=1 (green) 2 (blue) 3 (red) 4 (pink) 5 (orange) 6 (cyan)](#1,#2,#3)}

\begin{document}

    \begin{pspicture}(-4.5,-3.5)(6,6)
    \psset{Decran=60,viewpoint=80 10 15 rtp2xyz,lightsrc=viewpoint,solidmemory}
    \foreach \i/\j in {0.5/1,1.5/2,2.5/3}{\Figure{0.5}{\i}{0.5}{\j}}
    \foreach \i/\j in {1.5/4,2.5/5}{\Figure{\i}{.5}{0.5}{\j}}
    \Figure{1.5}{2.5}{0.5}{6}
    \foreach \i/\j in {1.5/7,2.5/8}{\Figure{2.5}{\i}{0.5}{\j}}
    \foreach \i/\j in {1.5/9,2.5/10}{\Figure{.5}{.5}{\i}{\j}}
    \Figure{2.5}{.5}{1.5}{11}
    \Figure{.5}{1.5}{2.5}{12}
    \foreach \i/\j in {1.5/13,2.5/14}{\Figure{\i}{.5}{2.5}{\j}}
    \Figure{2.5}{1.5}{2.5}{15}
    \foreach \i/\j in {1.5/16,2.5/17}{\Figure{.5}{2.5}{\i}{\j}}
    \Figure{1.5}{2.5}{2.5}{18}
    \foreach \i/\j in {1.5/19,2.5/20}{\Figure{2.5}{2.5}{\i}{\j}}
    \psSolid[object=fusion,
             base=c1 c2 c3 c4 c5 c6 c7 c8 c9 c10 c11 c12 c13 c14 c15 c16 c17 c18 c19 c20]
    \composeSolid
    \end{pspicture}
\end{document}

對於許多立方體，您可以簡化融合物件：

\def\cubes{}
\multido{\iA=1+1}{20}{\xdef\cubes{\cubes\space c\iA}}
\begin{pspicture} ....
    ....    
    \psSolid[object=fusion, base=\cubes]
    ....

這是構建完整立方體的方法：

\documentclass[pstricks]{standalone}
\usepackage{pst-solides3d}
\newcounter{fig}
\def\Figure#1#2#3{%
    \stepcounter{fig}%
    \psSolid[object=cube,name=c\thefig,ngrid=1,a=1,
             action=none,fcol=1 (green) 2 (blue) 3 (red) 4 (pink) 5 (orange) 6 (cyan)](#1,#2,#3)}

\begin{document}

    \begin{pspicture}(-5,-3.5)(4,6)
    \psset{Decran=60,viewpoint=80 60 15 rtp2xyz,lightsrc=viewpoint,solidmemory}
    \multido{\iA=0+1}{7}{%
      \multido{\iB=0+1}{7}{%
         \multido{\iC=0+1}{7}{%
           \Figure{\iB}{\iA}{\iC}%
    }}}%
    \psSolid[object=fusion, base=
    % 1
       c1   c2   c3   c4   c5   c6   c7
       c8        c10  c11  c12       c14
       c15  c16  c17  c18  c19  c20  c21
       c22  c23  c24       c26  c27  c28
       c29  c30  c31  c32  c33  c34  c35
       c36       c38  c39  c40       c42
       c43  c44  c45  c46  c47  c48  c49
    % 2
       c50       c52  c53  c54       c56
    %      
       c64       c66  c67  c68       c70
       c71       c73       c75       c77
       c78       c80  c81  c82       c84
    %      
       c92       c94  c95  c96       c98
     % 3 ...
      ]
    \composeSolid
    \end{pspicture}
\end{document}

和完整的圖像：

Answer 2

像這樣的東西嗎？

\documentclass[tikz,border=3.14mm]{standalone}
\usepackage{tikz-3dplot}
\usetikzlibrary{calc}
\tikzset{plane/.style n args={3}{insert path={%
#1 -- ++ #2 -- ++ #3 -- ++ ($-1*#2$) -- cycle}},
unit xy plane/.style={plane={#1}{(1,0,0)}{(0,1,0)}},
unit xz plane/.style={plane={#1}{(1,0,0)}{(0,0,1)}},
unit yz plane/.style={plane={#1}{(0,1,0)}{(0,0,1)}},
get projections/.style={insert path={%
let \p1=(1,0,0),\p2=(0,1,0)  in 
[/utils/exec={\pgfmathtruncatemacro{\xproj}{sign(\x1)}\xdef\xproj{\xproj}
\pgfmathtruncatemacro{\yproj}{sign(\x2)}\xdef\yproj{\yproj}
\pgfmathtruncatemacro{\zproj}{sign(cos(\tdplotmaintheta))}\xdef\zproj{\zproj}}]}},
pics/unit cube/.style={code={
\path[get projections];
\draw (0,0,0) -- (1,1,1);
\ifnum\zproj=-1
 \path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,0)}]; 
\fi
\ifnum\yproj=1
 \path[3d cube/every face,3d cube/yz face,unit yz plane={(1,0,0)}]; 
\else
 \path[3d cube/every face,3d cube/yz face,unit yz plane={(0,0,0)}]; 
\fi
\ifnum\xproj=1
 \path[3d cube/every face,3d cube/xz face,unit xz plane={(0,0,0)}]; 
\else
 \path[3d cube/every face,3d cube/xz face,unit xz plane={(0,1,0)}]; 
\fi
\ifnum\zproj>-1
 \path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,1)}]; 
\fi
}},
3d cube/.cd,
xy face/.style={fill=orange},
xz face/.style={fill=blue},
yz face/.style={fill=red},
every face/.style={draw,very thick}
}
\begin{document}
\foreach \Angle in {5,15,...,355} 
{\tdplotsetmaincoords{60}{\Angle} % the first argument cannot be larger than 90
\begin{tikzpicture}[line join=round]
 \pgfmathtruncatemacro{\NumCubes}{7}
 \path[use as bounding box] (-\NumCubes/2-3,-\NumCubes/2-2) 
 rectangle (\NumCubes/2+3,\NumCubes/2+4);
 \begin{scope}[tdplot_main_coords]
  \pgfmathtruncatemacro{\NextToLast}{\NumCubes-1}
  \path[get projections];
  \ifnum\yproj=1
   \def\LstX{1,...,\NumCubes}
  \else 
   \def\LstX{\NumCubes,\NextToLast,...,1}
  \fi
  \ifnum\xproj=-1
   \def\LstY{1,...,\NumCubes}
  \else 
   \def\LstY{\NumCubes,\NextToLast,...,1}
  \fi
  \ifnum\zproj=1
   \def\LstZ{1,...,\NumCubes}
  \else 
   \def\LstZ{\NumCubes,\NextToLast,...,1}
  \fi
  \foreach \X in \LstX
  {\foreach \Y in \LstY
   {\foreach \Z in \LstZ
    {\xdef\itest{1}
     \ifodd\X
     \else
       \pgfmathtruncatemacro{\jtest}{mod(\X+\Y,4)}
       \ifnum\jtest=0
        \xdef\itest{0}
       \fi
       \pgfmathtruncatemacro{\jtest}{mod(\X+\Z,4)}
       \ifnum\jtest=0
        \xdef\itest{0}
       \fi
     \fi
     \ifodd\Y
     \else
       \pgfmathtruncatemacro{\jtest}{mod(\Y+\Z,4)}
       \ifnum\jtest=0
        \xdef\itest{0}
       \fi
     \fi
     \ifnum\itest=1
     \path (\X-\NumCubes/2-1/2,\Y-\NumCubes/2-1/2,\Z-\NumCubes/2-1/2) pic{unit cube};
     \fi}}
  }
 \end{scope}
\end{tikzpicture}}
\end{document}