方程式數組超出右邊距

Question

我寫方程eqnarray用Latex寫方程，但有些行超出了右邊距，如何解？

這是我的程式碼：

\begin{eqnarray}    
    k_1&=&hf(t_i, y_i)=hf_i \label{$k_1$ RK-4}\\
    k_2&=&hf(t_i+p_1h, y_i+q_11_k1)\nonumber\\
       &=&h(f_i+p_1hf_t+q_{11}k_1f_y)\nonumber\\
       &=&h(f_i+p_1hf_t+q_{11}hf_if_y)\\    
    k_3&=&hf(t_i+p_2h,y_i+q_21k_1+q_22k_2)\nonumber\\
       &=&h(f_i+p_2hf_t+q_21k_1f_y+q_22k_2f_y)\nonumber\\
       &=&h(f_i+p_2hf_t+q_{21}hf_if_y+q_{22} h(f_i+p_1hf_t+q_{11}hf_if_y)f_y)\nonumber\\
       &=&h(f_i+p_2hf_t+q_{21}hf_if_y+q_{22}hf_if_y +q_22h^2p_1f_tf_y+q_{11}q{22}h^2f_i(f_y)^2)\\
    k_4&=&hf(t_i+p_3h, y_i+q_31k_1+q_32k_2+q_33k_3)\nonumber\\
       &=&h(f_i+p_3hf_t+q_{31}k_1f_y+q_{32}k_2f_y+q_{33}k_3f_y)\nonumber\\
       &=&h(f_i+p_3hf_t+q_{31}hf_if_y+q_{32} h(f_i+p_1hf_t+q_{11}hf_if_y)f_y +q_{33}h(f_i+p_2hf_t+q_{21}hf_if_y+q_{22}hf_if_y+q_{22}h^2p_1f_tf_y+q_{21}q_{22}h^2f_i(f_y)^2)f_y)\nonumber\\
       &=&h(f_i+p_3hf_t+q_{31}hf_if_y+q_{32}hf_if_y +p_1q_{32}h^2f_tf_y +q_{11}q_{32}h^2f_i(f_y)^2+q_{33}hf_if_y+p_2q_{33}h^2f_tf_y+q_{21}q_{33}h^2f_i(f_y)^2+q_{22}q_{33}h^2f_i(f_y)^2+q_{22}q_{33}p_1h^3f_t(f_y)^2+q_{11}q_{22}q_{33}h^3f_i(f_y)^3)\\
\end{eqnarray}

這是結果：

Answer 1

除了不使用的標準建議之外eqnarray除了出於任何原因eqnarray 與對齊，我建議split為此使用，以便將每個區塊劃分為一個單元。

透過該tbtags選項，我們可以確保將方程式所附的數字split加到底部（當方程式編號位於右側時）或頂部。

\documentclass{article}
\usepackage[tbtags]{amsmath} % for math

\begin{document}
\begin{align}    
k_1 &= hf(t_i, y_i)=hf_i \label{k1_RK_4}
\\
\begin{split}
k_2 &= hf(t_i+p_1h, y_i+q_{11}k_1) \\
    &= h(f_i+p_1hf_t+q_{11}k_1f_y) \\
    &= h(f_i+p_1hf_t+q_{11}hf_if_y)
\end{split}
\\
\begin{split}
k_3 &= hf(t_i+p_2h, y_i+q_{21}k_1+q_{22}k_2) \\
    &= h(f_i+p_2hf_t+q_{21}k_1f_y+q_{22}k_2f_y) \\
    &= h[f_i+p_2hf_t+q_{21}hf_if_y+q_{22}h(f_i+p_1hf_t+q_{11}hf_if_y)f_y] \\    
    &= h[f_i+p_2hf_t+q_{21}hf_if_y+q_{22}hf_if_y+q_{22}h^2p_1f_tf_y+
       q_{11}q_{22}h^2\!f_i(f_y)^2]
\end{split}
\\
\begin{split}
k_4 &= hf(t_i+p_3h, y_i+q_{31}k_1+q_{32}k_2+q_{33}k_3) \\
    &= h(f_i+p_3hf_t+q_{31}k_1f_y+q_{32}k_2f_y+q_{33}k_3f_y) \\
    &= h\{f_i+p_3hf_t+q_{31}hf_if_y+q_{32}h(f_i+p_1hf_t+q_{11}hf_if_y)f_y \\
    &\qquad +q_{33}h[f_i+p_2hf_t+q_{21}hf_if_y+q_{22}hf_if_y+q_{22}h^2p_1f_tf_y \\
    &\qquad +q_{21}q_{22}h^2\!f_i(f_y)^2]f_y\} \\
    &= h\{f_i+p_3hf_t+q_{31}hf_if_y+q_{32}hf_if_y+p_1q_{32}h^2\!f_tf_y+
       q_{11}q_{32}h^2\!f_i(f_y)^2 \\
    &\qquad +q_{33}hf_if_y+p_2q_{33}h^2\!f_tf_y+q_{21}q_{33}h^2\!f_i(f_y)^2+
     q_{22}q_{33}h^2\!f_i(f_y)^2 \\
    &\qquad+q_{22}q_{33}p_1h^3\!f_t(f_y)^2+q_{11}q_{22}q_{33}h^3\!f_i(f_y)^3\}
\end{split}
\end{align}

\end{document}

Answer 2

q_11除了在最後兩行中手動插入一些換行符之外，q_21您還需要根據需要在術語 、 、 等中添加大括號來修復一些符號q_22。之外還使用方括號和花括號，它可以幫助讀者偵測括號的順序。_k1k_1

你絕對應該不是正在使用嚴重棄用的eqnarray環境。請改用包包align提供的環境amsmath。

\documentclass{article}
\usepackage{amsmath} % for 'align' environment and '\notag' macro

\begin{document}
\begin{align}    
    k_1 &= hf(t_i, y_i)=hf_i \label{k1_RK_4}\\
    k_2 &= hf(t_i+p_1h, y_i+q_{11}k_1) \notag\\
     &= h(f_i+p_1hf_t+q_{11}k_1f_y) \notag\\
     &= h(f_i+p_1hf_t+q_{11}hf_if_y)\\   
    k_3 &= hf(t_i+p_2h, y_i+q_{21}k_1+q_{22}k_2)  \notag\\
     &= h(f_i+p_2hf_t+q_{21}k_1f_y+q_{22}k_2f_y) \notag\\
     &= h[f_i+p_2hf_t+q_{21}hf_if_y+q_{22}h(f_i+p_1hf_t+q_{11}hf_if_y)f_y] \notag\\    
     &= h[f_i+p_2hf_t+q_{21}hf_if_y+q_{22}hf_if_y+q_{22}h^2p_1f_tf_y+q_{11}q_{22}h^2\!f_i(f_y)^2]\\
    k_4 &= hf(t_i+p_3h, y_i+q_{31}k_1+q_{32}k_2+q_{33}k_3) \notag\\
     &= h(f_i+p_3hf_t+q_{31}k_1f_y+q_{32}k_2f_y+q_{33}k_3f_y) \notag\\
     &= h\{f_i+p_3hf_t+q_{31}hf_if_y+q_{32}h(f_i+p_1hf_t+q_{11}hf_if_y)f_y \notag\\
     &\qquad +q_{33}h[f_i+p_2hf_t+q_{21}hf_if_y+q_{22}hf_if_y+q_{22}h^2p_1f_tf_y \notag\\
     &\qquad +q_{21}q_{22}h^2\!f_i(f_y)^2]f_y\} \notag\\   
     &= h\{f_i+p_3hf_t+q_{31}hf_if_y+q_{32}hf_if_y+p_1q_{32}h^2\!f_tf_y+q_{11}q_{32}h^2\!f_i(f_y)^2 \notag\\
     &\qquad +q_{33}hf_if_y+p_2q_{33}h^2\!f_tf_y+q_{21}q_{33}h^2\!f_i(f_y)^2+q_{22}q_{33}h^2\!f_i(f_y)^2 \notag\\
     &\qquad+q_{22}q_{33}p_1h^3\!f_t(f_y)^2+q_{11}q_{22}q_{33}h^3\!f_i(f_y)^3\}
\end{align}
\end{document}