
\begin{table}[h!]
\centering
\begin{tabular}{l|c |c |c |c |c |c}
1 & 2 & 3 & 4jkjhkjkhjhkjkjkjl & 5fsdsadsadasdsadsadasdsadsa & 6dasdsadasdasdasdasdsadasdsa \\
\hline
1 & 2 & 3 \\
1 & 2 & 3 \\
\end{tabular}
\caption{tes}
\label{tab:my_label}
\end{table}
輸出:
如何將「5fsdsadsadasdsadsadasdsadsa」變成2行?例如:
5fsdsadsadasd
sadsadasdsadsa
答案1
你還沒有表明有多寬第 4、5 和 6 列應該是。因此,我假設他們應該是同樣寬。我將進一步假設表格材料的整體寬度應該\textwidth
與文字區塊一樣寬。下面的程式碼使用了一個tabularx
環境和三列類型X
。
由於沒有明顯的方法 - 至少對我來說...... - 來決定字符串“5fsdsadsadasdsadsadasdsadsa”和“6dasdsadasdasdasdasdsadasdsa”應該在哪裡分割,我將使用宏\seqsplit
來強制在字符串到達時發生換行各個單元格的寬度。
\documentclass{article}
\usepackage{tabularx,seqsplit}
\begin{document}
\begin{table}[h!]
\setlength\extrarowheight{2pt} % for a ever so slightly more open "look"
\begin{tabularx}{\textwidth}{|c |c |c |X |X |X |}
\hline
1 & 2 & 3 &
\seqsplit{4jkjhkjkhjhkjkjkjl} &
\seqsplit{5fsdsadsadasdsadsadasdsadsa} &
\seqsplit{6dasdsadasdasdasdasdsadasdsa} \\
\hline
1 & 2 & 3 & & & \\
1 & 2 & 3 & & & \\
\hline
\end{tabularx}
\caption{tes}
\label{tab:my_label}
\end{table}
\end{document}
答案2
\documentclass{article}
\begin{document}
\begin{table}[htp]% h on its own is asking for trouble
\centering
\begin{tabular}{l|c |c |c |c |c |c}
1 & 2 & 3 & 4jkjhkjkhjhkjkjkjl &
\begin{tabular}{@{}c@{}}5fsdsadsadasd\\sadsadasdsadsa\end{tabular} &
\begin{tabular}{@{}c@{}}6dasdsadasdasd\\asdasdsadasdsa\end{tabular} \\
\hline
1 & 2 & 3 \\
1 & 2 & 3 \\
\end{tabular}
\caption{tes}
\label{tab:my_label}
\end{table}
\end{document}