下面的程式碼給出了一個框圖，由兩個區塊 P(s) 和 C(s) 組成。這兩個區塊也在列表中作為單獨的項目給出，並且每個區塊在單擊滑鼠後出現。為了吸引觀眾的注意力，我希望當 P(s) 的第一個項目符號出現在第一張投影片中時，框圖中顯示 P(s) 的相應圓角矩形應該著色。並且，當 C(s) 的第二個項目出現時，框圖中 C(s) 的圓角矩形應該會變成彩色。我怎樣才能做到這一點？
\documentclass[compress, xcolor=table, usenames,dvipsnames]{beamer}
\usepackage{tikz}
\begin{document}
\tikzset{every picture/.style={line width=0.75pt}} %set default line width to 0.75pt
\begin{frame}{Figure}
\begin{tikzpicture}[x=0.75pt,y=0.75pt,yscale=-1,xscale=1]
%uncomment if require: \path (0,235); %set diagram left start at 0, and has
height of 235
%Rounded Rect [id:dp22728745820859309]
\draw (134,66.75) .. controls (134,62.33) and (137.58,58.75) ..
(142,58.75) -- (196,58.75) .. controls (200.42,58.75) and (204,62.33) ..
(204,66.75) -- (204,90.75) .. controls (204,95.17) and (200.42,98.75) ..
(196,98.75) -- (142,98.75) .. controls (137.58,98.75) and (134,95.17) ..
(134,90.75) -- cycle ;
%Rounded Rect [id:dp23074367111159821]
\draw (254,64.75) .. controls (254,60.33) and (257.58,56.75) ..
(262,56.75) -- (316,56.75) .. controls (320.42,56.75) and (324,60.33) ..
(324,64.75) -- (324,88.75) .. controls (324,93.17) and (320.42,96.75) ..
(316,96.75) -- (262,96.75) .. controls (257.58,96.75) and (254,93.17) ..
(254,88.75) -- cycle ;
%Straight Lines [id:da3785057523496602]
\draw (205,77.75) -- (251.5,76.79) ;
\draw [shift={(253.5,76.75)}, rotate = 538.8199999999999] [color={rgb,
255:red, 0; green, 0; blue, 0 } ][line width=0.75] (10.93,-3.29) ..
controls (6.95,-1.4) and (3.31,-0.3) .. (0,0) .. controls (3.31,0.3) and
(6.95,1.4) .. (10.93,3.29) ;
%Shape: Circle [id:dp7405273795099738]
\draw (350,76.5) .. controls (350,66.7) and (357.95,58.75) ..
(367.75,58.75) .. controls (377.55,58.75) and (385.5,66.7) .. (385.5,76.5)
.. controls (385.5,86.3) and (377.55,94.25) .. (367.75,94.25) .. controls
(357.95,94.25) and (350,86.3) .. (350,76.5) -- cycle ;
%Straight Lines [id:da4768143479707079]
\draw (323.75,77) -- (349.25,77) ;
\draw [shift={(351.25,77)}, rotate = 180] [color={rgb, 255:red, 0; green,
0; blue, 0 } ][line width=0.75] (10.93,-3.29) .. controls (6.95,-1.4)
and (3.31,-0.3) .. (0,0) .. controls (3.31,0.3) and (6.95,1.4) ..
(10.93,3.29) ;
%Shape: Circle [id:dp9725542364076398]
\draw (70,78.5) .. controls (70,68.7) and (77.95,60.75) .. (87.75,60.75)
.. controls (97.55,60.75) and (105.5,68.7) .. (105.5,78.5) .. controls
(105.5,88.3) and (97.55,96.25) .. (87.75,96.25) .. controls (77.95,96.25)
and (70,88.3) .. (70,78.5) -- cycle ;
%Straight Lines [id:da10367925110615261]
\draw (105.5,78.5) -- (135.75,78.5) ;
\draw [shift={(137.75,78.5)}, rotate = 180] [color={rgb, 255:red, 0;
green, 0; blue, 0 } ][line width=0.75] (10.93,-3.29) .. controls
(6.95,-1.4) and (3.31,-0.3) .. (0,0) .. controls (3.31,0.3) and (6.95,1.4)
.. (10.93,3.29) ;
%Straight Lines [id:da3384320385828452]
\draw (87.75,136) -- (341.75,136) ;
%Straight Lines [id:da9706282263267894]
\draw (341.75,136) -- (341.75,77) ;
%Straight Lines [id:da01968558683101662]
\draw (87.75,137) -- (87.75,96.25) ;
% Text Node
\draw (289,76.75) node [align=left] {P(s)};
\draw (169,76.75) node [align=left] {C(s)};
% Text Node
\end{tikzpicture}
\beamerdefaultoverlayspecification{<+->}
\begin{itemize}
\item P(s)
\item C(s)
\end{itemize}
\end{frame}
\end{document}
答案1
我很佩服你一步步用貝塞爾曲線畫出長方形和圓形的勇氣和耐心。
如果您能夠做到這一點，您可能有興趣知道 TikZ 已計劃自動完成所有這些計算。
為此目的，TikZ 創造了所謂的node. Anode是包含文字的圓形、長方形或其他形狀。
使用節點的優點是 tikz 聰明地繪製從一個節點到另一個節點的箭頭。也就是說，箭頭從一個邊緣延伸到另一個邊緣，並且不會穿透（除非要求）內部node。
我冒昧地（並且道歉）透過使用 Tikz 節點的較短程式碼刪除了您非常好的程式碼。但我把你的尺寸保留在 pt 中。
使用 www.DeepL.com/Translator 翻譯（免費版本）
\documentclass[compress, xcolor=table, usenames,dvipsnames]{beamer}
\usepackage{tikz}
\usetikzlibrary{positioning,calc}
\begin{document}
\tikzset{every picture/.style={line width=0.75pt}, %set default line width to 0.75pt
skip loop/.style={to path={--++(0,25pt) -| (\tikztotarget)}},
filled/.style={draw,rectangle,minimum height=30pt,fill=yellow,minimum width=50pt,rounded corners},
unfilled/.style={draw,rectangle,minimum height=30pt,minimum width=50pt,rounded corners},
cercle/.style={draw,circle,minimum size=25pt}}
\begin{frame}{Figure}
\begin{tikzpicture}[x=0.75pt,y=0.75pt,yscale=-1,xscale=1]
\node[cercle](initial) at (80,78.5){};
\node[unfilled,right =of initial](second){C(s)};
\node[unfilled,right = 39pt of second](third){P(s)};
\node[cercle,right =21pt of third](terminal){};
\draw[->](initial)--(second)--(third)--(terminal);
\path[blue,->] (initial)edge[skip loop]($(third.east)!.5!(terminal.west)$);
\node<1>[filled]at(third){P(s)};
\node<2>[filled]at(second){C(s)};
\end{tikzpicture}
%\beamerdefaultoverlayspecification{<+->}
\begin{itemize}[<+->]
\item P(s)
\item C(s)
\end{itemize}
\end{frame}
\end{document}
答案2
讓我基本上重複一下我的先前的回答這裡。讓我提一下，有一個包overlay-beamer-styles正是針對這種情況而設計的。它可以讓您免於過度繪製事物並防止跳躍。你只需要說
\node[box,highlight on=<1>](B1){$\mathsf{C}(\mathsf{s})$};
反白顯示C第一張投影片上的節點。
\documentclass{beamer}
\usepackage{tikz}
\usetikzlibrary{chains,overlay-beamer-styles}
\tikzset{highlight on/.style args={<#1>}{alt=<#1>{fill=yellow}}}
\begin{document}
\begin{frame}[t] % https://tex.stackexchange.com/a/518055/194703
\frametitle{A scintillator}
\begin{center}
\begin{tikzpicture}[circ/.style={circle,inner sep=3.2mm,draw},
box/.style={draw,rounded corners=3pt,minimum width=16mm,minimum height=8mm},
line width=0.75pt]
\begin{scope}[start chain=going right,nodes={on chain,join},
every join/.style={-stealth}]
\node[circ](C1){};
\node[box,highlight on=<1>](B1){$\mathsf{C}(\mathsf{s})$};
\node[box,highlight on=<2>](B2){$\mathsf{P}(\mathsf{s})$};
\node[circ](C2){};
\end{scope}
\path (B2.east) -- coordinate (aux)(C2.west) ;
\draw[-stealth](aux) --++ (0,-1cm) -| (C1);
\end{tikzpicture}
\end{center}
\begin{itemize}[<+->]
\item P(s)
\item C(s)
\end{itemize}
\end{frame}
\end{document}
