
我想弄清楚為什麼我無法在節點之間水平居中繪製一條藍色實線?
\documentclass{article}
\usepackage{tikz,amsmath}
\usetikzlibrary{positioning}
\begin{document}
\begin{center}
\begin{tikzpicture}
\node(X)[draw,rectangle, rounded corners,draw=black,
fill=white,align=center,xshift=-6cm]
{\large Input \textcolor{red}{$2$}};%
\node(Y)[draw,rectangle, rounded corners,draw=black,
fill=white,align=center,xshift=-.5cm]
{\large $\begin{aligned}[t] g(\textcolor{red}
{2})&=\textcolor{red}{2}^{2}+1\\ &=5\end{aligned}$\\
\large The output of $g$, \textcolor{blue}{$5$},is\\
\large the input to $f$};%
\node (Z)[draw,rectangle, rounded corners,draw=black,
fill=white,align=center,xshift=6cm]
{\large $\begin{aligned}[t] f(\textcolor{blue}
{5})&=4(\textcolor{blue}{5})-3\\ &=17\end{aligned}$};%
\end{tikzpicture}
\end{center}
\begin{tikzpicture}
\draw[blue,thick,-latex] (X.east) to ( Y.west);
\end{tikzpicture}
\end{document}
答案1
假設您想要有兩個單獨的tikzpicture
s,則需要分別添加remember picture
和overlay,remember picture
。
\documentclass{article}
\usepackage{tikz,amsmath}
\usetikzlibrary{positioning}
\begin{document}
\begin{center}
\begin{tikzpicture}[remember picture]
\node(X)[draw,rectangle, rounded corners,draw=black,
fill=white,align=center,xshift=-6cm]
{\large Input \textcolor{red}{$2$}};%
\node(Y)[draw,rectangle, rounded corners,draw=black,
fill=white,align=center,xshift=-.5cm]
{\large $\begin{aligned}[t] g(\textcolor{red}
{2})&=\textcolor{red}{2}^{2}+1\\ &=5\end{aligned}$\\
\large The output of $g$, \textcolor{blue}{$5$},is\\
\large the input to $f$};%
\node (Z)[draw,rectangle, rounded corners,draw=black,
fill=white,align=center,xshift=6cm]
{\large $\begin{aligned}[t] f(\textcolor{blue}
{5})&=4(\textcolor{blue}{5})-3\\ &=17\end{aligned}$};%
\end{tikzpicture}
\end{center}
\begin{tikzpicture}[overlay,remember picture]
\draw[blue,thick,-latex] (X.east) to ( Y.west);
\end{tikzpicture}
\end{document}
當然,您可以只使用一個tikzpicture
。
\documentclass{article}
\usepackage{tikz,amsmath}
\usetikzlibrary{positioning}
\begin{document}
\begin{center}
\begin{tikzpicture}
\node(X)[draw,rectangle, rounded corners,draw=black,
fill=white,align=center,xshift=-6cm]
{\large Input \textcolor{red}{$2$}};%
\node(Y)[draw,rectangle, rounded corners,draw=black,
fill=white,align=center,xshift=-.5cm]
{\large $\begin{aligned}[t] g(\textcolor{red}
{2})&=\textcolor{red}{2}^{2}+1\\ &=5\end{aligned}$\\
\large The output of $g$, \textcolor{blue}{$5$},is\\
\large the input to $f$};%
\node (Z)[draw,rectangle, rounded corners,draw=black,
fill=white,align=center,xshift=6cm]
{\large $\begin{aligned}[t] f(\textcolor{blue}
{5})&=4(\textcolor{blue}{5})-3\\ &=17\end{aligned}$};%
\draw[blue,thick,-latex] (X.east) to ( Y.west);
\end{tikzpicture}
\end{center}
\end{document}
兩個程式碼的輸出都是
答案2
受到薛丁格的貓答案中第二個例子的啟發。透過使用庫chains
和他的宏join
,定位並定義所有節點的通用樣式:
\documentclass{article}
\usepackage{tikz,amsmath}
\usetikzlibrary{chains,
positioning}
\begin{document}
\begin{center}
\begin{tikzpicture}[
node distance = 22mm,
start chain = going right,
box/.style = {draw, rounded corners, font=\large,
align=center, on chain},
every join/.style = {blue,thick,-latex}
]
\node (X) [box] {Input \textcolor{red}{$2$}};%
\node (Y) [box, join]
{$\begin{aligned}[t]
g(\textcolor{red}{2}) & = \textcolor{red}{2}^{2}+1\\
& = 5
\end{aligned}$\\
The output of $g$, \textcolor{blue}{$5$}, \\
is the input to $f$};
\node (Z) [box] {$\begin{aligned}[t]
f(\textcolor{blue}{5}) & = 4(\textcolor{blue}{5})-3\\
& = 17
\end{aligned}$};%
\end{tikzpicture}
\end{center}
\end{document}