如何在 LaTeX 中的align*多長方程式中使用大括號？

Question

\left(這是我的程式碼，但當我更改為\right)和\Big)時它不起作用\Big)

\begin{align*}
\bar{h}_{m}^{jk}&=\omega_{k}h_{m}^{jk}(a)\\
&=\left(  \omega_{k}\left\{
\zeta_{h}\mid\zeta_{h}\in p_{1}\circ h_{m}^{jk}(a)\right\}  ,\omega
_{k}\left\{  \zeta_{h}\mid\zeta_{h}\in p_{2}\circ h_{m}^{jk}(a)\right\}
,\dots, \right.\\
 &\qquad \left.\omega_{k}\left\{  \zeta_{h}\mid\zeta_{h}\in p_{m}\circ h_{m}%
^{jk}(a)\right\}  \right)  \\
&=\left(  \left\{  \bar{\zeta}_{h}\mid\bar{\ze
}_{h}\in p_{1}\circ h_{m}^{jk}(a)\right\}  ,\left\{  \bar{\zeta}_{h}\mid
\bar{\zeta}_{h}\in p_{2}\circ h_{m}^{jk}(a)\right\}  ,\dots,\left\{  \bar{\zeta
}_{h}\mid\bar{\zeta}_{h}\in p_{m}\circ h_{m}^{jk}(a)\right\}  \right)  .
\end{align*}

Answer 1

每個\left總是與 a 配對\right，且該配對不能與&or交叉\\。無論誰編寫了您的程式碼，實際上（正確地）\left(與\right.和\left.配對\right)；這.意味著 TeX 不會排版柵欄，但現在知道要測量多少尺寸。

更改\left(為\Big(和\right)to\Big)意味著您要離開\left.並\right.進入那裡，TeX 會對您要配對的內容感到困惑。解決方案是，當您更改\left(為\Big(和\right)時\Big)，您還需要刪除現在多餘的\left.和\right.。

順便說一句，出於間距目的，您可能需要使用\Bigl(和\Bigr)。這告訴 TeX 它正在處理左柵欄或右柵欄。

Answer 2

像這樣？

\documentclass{article}
\usepackage{mathtools}

\begin{document}
\begin{align*}
\bar{h}_{m}^{jk}
    & = \omega_{k}h_{m}^{jk}(a)\\
    & = \begin{multlined}[t]
    \biggl(\omega_{k}\Bigl\{
        \zeta_{h}\mid\zeta_{h}\in p_{1}\circ h_{m}^{jk}(a)\Bigr\},\omega_{k}
            \Bigl\{\zeta_{h}\mid\zeta_{h}\in p_{2}\circ h_{m}^{jk}(a)
                    \Bigr\}, \dots \\
    \dots, 
    \omega_{k}\Bigl\{\zeta_{h}\mid\zeta_{h}\in p_{m}\circ h_{m}^{jk}(a)
              \Bigr\}
    \biggr)
    \end{multlined} \\
    & = \begin{multlined}[t]
    \biggl(\Bigl\{\bar{\zeta}_{h}\mid\bar{\zeta}_{h}\in p_{1}\circ h_{m}^{jk}(a)\Bigr\},
           \Bigl\{\bar{\zeta}_{h}\mid\bar{\zeta}_{h}\in p_{2}\circ h_{m}^{jk}(a)
           \Bigr\},\dots         \\
    \dots,
           \Bigl\{\bar{\zeta}_{h}\mid\bar{\zeta}_{h}\in p_{m}\circ h_{m}^{jk}(a)\Bigr\}
    \biggr).
    \end{multlined}
\end{align*}
\end{document}

（紅線顯示文字邊框）

附錄： 使用 usealigned而不是multilined可以定義錨點，其中是多線方程式的對齊線：

\documentclass{article}
\usepackage{amsmath}

\begin{document}
\begin{align*}
\bar{h}_{m}^{jk}
    & = \omega_{k}h_{m}^{jk}(a)\\
    & = \begin{aligned}[t]
        \biggl(\omega_{k}\Bigl\{
        \zeta_{h}\mid\zeta_{h}\in p_{1}\circ h_{m}^{jk}(a)\Bigr\},
        &   \;\omega_{k}\Bigl\{\zeta_{h}\mid\zeta_{h}\in p_{2}\circ h_{m}^{jk}(a)\Bigr\}, \dots \\
    \dots,
        &   \;\omega_{k}\Bigl\{\zeta_{h}\mid\zeta_{h}\in p_{m}\circ h_{m}^{jk}(a)\Bigr\}\biggr)
        \end{aligned} \\
    & = \begin{aligned}[t]
        \biggl(\Bigl\{\bar{\zeta}_{h}\mid\bar{\zeta}_{h}\in p_{1}\circ h_{m}^{jk}(a)\Bigr\},
        &\; \Bigl\{\bar{\zeta}_{h}\mid\bar{\zeta}_{h}\in p_{2}\circ h_{m}^{jk}(a)\Bigr\},\dots \\
    \dots,
        &\; \Bigl\{\bar{\zeta}_{h}\mid\bar{\zeta}_{h}\in p_{m}\circ h_{m}^{jk}(a)\Bigr\}\biggr).
    \end{aligned}
\end{align*}
\end{document}

Answer 3

我建議這個變體使用稍微簡單的程式碼，基於 fleqnfrom nccmath、\DeclarePairedDelimiter命令 frommathtools和multlined環境（相同的套件）。

\documentclass[svgnames]{article}
\usepackage{showframe}
\renewcommand{\ShowFrameLinethickness}{0.4pt}
\renewcommand{\ShowFrameColor}{\color{Coral}}
 \usepackage{nccmath, mathtools}
 \DeclarePairedDelimiter\set\{\}

\begin{document}
\leavevmode\vskip 1cm

\begin{fleqn}
\begin{align*}
\bar{h}_{m}^{jk} &=\omega_{k}h_{m}^{jk}(a) \\
&=\begin{multlined}[t][0.9\linewidth]\Bigl( \omega_{k}\set*{\zeta_{h}\mid\zeta_{h}\in p_{1}\circ h_{m}^{jk}(a)} ,\omega
_{k}\set{ \zeta_{h}\mid\zeta_{h}\in p_{2}\circ h_{m}^{jk}(a)},\dots \\[-1.5ex]
\dots, \omega_{k}\set*{ \zeta_{h}\mid\zeta_{h}\in p_{m}\circ h_{m}^{jk}(a)}\Bigr) \end{multlined} \\
&= \begin{multlined}[t][0.9\linewidth]\Bigl( \set*{ \bar{\zeta}_{h}\mid\bar{\zeta}_{h}\in p_{1}\circ h_{m}^{jk}(a)} ,%
\set*{ \bar{\zeta}_{h}\mid \bar{\zeta}_{h}\in p_{2}\circ h_{m}^{jk}(a)} ,\dots \phantom{.} \\[-1.5ex]
\dots, \set*{ \bar{\zeta}_{h}\mid\bar{\zeta}_{h}\in p_{m}\circ h_{m}^{jk}(a)} \Bigr).
\end{multlined}
\end{align*}
\end{fleqn}

\end{document}