繪製的線未落在端點處

Question

我正在做一個構造，包括用一條線連接兩點。不知何故，從 K 到 E 的第一行沒問題，但從 K 到 M 的第一行不行。怎麼解決這個問題呢？附帶問題：是否有更簡單的方法將角度 <OBA 除以 4？

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{tikz}
\usepackage{amsmath,amssymb,amsthm,amsfonts,thmtools}
\usepackage[top=1in,bottom=1in,right=1in,left=1in]{geometry}
\usetikzlibrary{tikzmark, shapes, arrows, calc, intersections, through, backgrounds}
\newcommand{\tikzAngleOfLine}{\tikz@AngleOfLine}
\def\tikz@AngleOfLine(#1)(#2)#3{%
    \pgfmathanglebetweenpoints{%
        \pgfpointanchor{#1}{center}}{%
        \pgfpointanchor{#2}{center}}
    \pgfmathsetmacro{#3}{\pgfmathresult}%
}

\begin{document}

\begin{tikzpicture}[scale=12,cap=round,>=latex]

% draw the coordinates
\draw[thin, name path=x] (-0.2cm,0cm) -- (1.1cm,0cm);
\draw[thin, name path=y] (0cm,-0.1cm) -- (0cm,0.4cm);

\coordinate (O) at (0cm,0cm) node[below left=3pt]{$O$};
\coordinate (A) at (1cm,0cm);
\coordinate (B) at (0cm,0.25cm);

\draw[thin] (A) circle(0.1pt) node[below=3pt]{$A$} -- (B) circle(0.1pt) node[left]{$B$};
\tikzAngleOfLine(B)(O){\AngleStart};
\tikzAngleOfLine(B)(A){\AngleEnd};
\pgfmathsetmacro{\alp}{(\AngleEnd+3*\AngleStart)/4};

\draw[thin,red, name path=BE] (B) -- ++(\alp:0.3cm);
\path [name intersections={of=BE and x,by=E}];
\draw (E) circle(0.1pt) node[below left=3pt]{$E$};

\draw[thin,blue, name path=BF] (B) -- ++(\alp-45:0.3cm);
\path [name intersections={of=BF and x,by=F}];
\draw (F) circle(0.1pt) node[below left=3pt]{$F$};

\node (M) [] at ($(F)!0.5!(A)$) {};
\pgfgetlastxy{\xM}{\yM}
\draw (M) circle(0.1pt) node[below left=3pt]{$M$};
\pgfmathsetmacro{\rM}{1-\xM*1pt/1cm*1/12};

\draw[thin, name path=AF] ([shift=(0:\rM)] M) arc (0:180:\rM);

\path[name intersections={of=AF and y,by=K},fill=black];
\draw (K) circle(0.1pt) node[above left=3pt]{$K$};
\draw[thin,green] (K) -- (E); % neatly landing in E
\draw[thin,green] (K) -- (M); % why not landing in M?

\end{tikzpicture}

\end{document}

Answer 1

這裡的一般答案是使用\coordinate而不是\node. Acoordinate實際上是一種特定類型的節點，但它不像文字方塊那樣工作，它只是一個點。即使是空的也\node有大小，並且繪製到節點的線在節點邊界處停止。

然而，\coordinate在這裡使用似乎會混亂\pgfgetlastxy，所以有幾個替代方案

• \path (M);指定座標後追加：

  \coordinate(M) at ($(F)!0.5!(A)$); \path (M);
  

  這樣就\pgfgetlastxy可以找到正確的點（看起來）。

• 繪製到center的錨點M：

  \draw[thin,green] (K) -- (M.center);