這是我的 mwe.tex
\documentclass[12pt]{report}
\usepackage{xifthen}
\usepackage{xstring}
\def\test{\textnormal{test}}
\newcounter{wordCount}
\setcounter{wordCount}{0}
\newcounter{AllWord}
\setcounter{AllWord}{0}
\NewDocumentCommand{\exy}{ m m m}{%
\StrCount{#2}{,}[\comma]
\StrCount{#2}{?}[\qmark]
\ifthenelse{\qmark > 0}{%
\addtocounter{wordCount}{\comma + \qmark}
\addtocounter{AllWord}{\comma + \qmark}
}{%
\addtocounter{wordCount}{\comma + \qmark + 1}
\addtocounter{AllWord}{\comma + \qmark + 1}
}
\textbf{#2} (#3), ``#1''\\%
}
\begin{document}
\test\par
\exy{one \test}{two \test s}{three \test s}
\end{document}
如果您註解掉該行,\exy
它將按預期工作。否則錯誤開始於
[{
"resource": "/c:/Users/hsmye/LaTeX/Gaelic/vocab/mwe.tex",
"owner": "LaTeX",
"severity": 8,
"message": "Undefined control sequence.\n\\reserved@a ->\\@nil",
"source": "LaTeX",
"startLineNumber": 27,
"startColumn": 1,
"endLineNumber": 27,
"endColumn": 65536
}]
這超出了我的宏福範圍。有人可以幫忙嗎?需要注意的是,這並不是最初的問題。為了在不需要購買字體的情況下生成 MWE,我不斷取出直到沒有錯誤,然後添加回去以獲得這個。原來的問題是:
\newfontfamily{\EtGoudy}{P22 Goudy Ampersands}
\DeclareTextFontCommand{\GoudyEt}{\EtGoudy}
\newfontfamily{\cVirgi}{P22 Virginian}
\DeclareTextFontCommand{\Virgic}{\cVirgi}
\def\dispEt{\GoudyEt{c}\kern -3pt{\vspace{-0.01ex}\huge\Virgic{c}}.}
\def\Etc{\textnormal{\dispEt}}
替換\test
為\Etc
具有類似結果。
答案1
請注意,您應該始終以多行形式顯示 TeX 錯誤,因為換行符號對於理解訊息至關重要,它們標記哪個命令未定義
! Undefined control sequence.
\reserved@a ->\@nil
l.29 ...exy{one \test}{two \test s}{three \test s}
?
您使用了 TeX 原語定義,導致了一個脆弱的命令在擴充上下文中中斷。如果您使用,\NewDocumentCommand
您可以\protected
在此類結構中獲得命令安全。
這運行沒有錯誤
\documentclass[12pt]{report}
\usepackage{xifthen}
\usepackage{xstring}
\NewDocumentCommand\test{}{\textnormal{test}}
\newcounter{wordCount}
\setcounter{wordCount}{0}
\newcounter{AllWord}
\setcounter{AllWord}{0}
\NewDocumentCommand{\exy}{ m m m}{%
\StrCount{#2}{,}[\comma]%%%%%%%%%%%%%%
\StrCount{#2}{?}[\qmark]%%%%%%%%%%%%%%
\ifthenelse{\qmark > 0}{%
\addtocounter{wordCount}{\comma + \qmark}%%%%%%%%%%%%%%
\addtocounter{AllWord}{\comma + \qmark}%%%%%%%%%%%%%%
}{%
\addtocounter{wordCount}{\comma + \qmark + 1}%%%%%%%%%%%%%%
\addtocounter{AllWord}{\comma + \qmark + 1}%%%%%%%%%%%%%%
}%%%%%%%%%%%%%%
\textbf{#2} (#3), ``#1''\\%
}
\begin{document}
\test\par
\exy{one \test}{two \test s}{three \test s}
\end{document}
但產生
Underfull \hbox (badness 10000) in paragraph at lines 29--30
由於位置錯誤\\
,絕不應該在段落末尾使用它。 (使用的話會更好\par
)
答案2
我不會用xstring
。程式碼中的主要問題是該命令\Etc
(非常)脆弱。
我的建議是expl3
透過分割逗號和問號的文字並計算項目數(並減一)來計算逗號和問號的數量。
該參數被完全擴展(但健壯的命令沒有)和“純化”,因此諸如此類的命令\textnormal
消失了。
\documentclass[12pt]{report}
\newcommand\test{\textnormal{test}}
\NewDocumentCommand\dispEt{}{\GoudyEt{c}\kern -3pt{\huge\Virgic{c}}.}
\NewDocumentCommand\Etc{}{\textnormal{\dispEt}}
\newcommand\GoudyEt{}% just for testing
\newcommand{\Virgic}{}% just for testing
\newcounter{wordCount}
\newcounter{AllWord}
\ExplSyntaxOn
\NewDocumentCommand{\exy}{m m m}
{
\hsmyers_xyz_exy:nnen { #1 } { #2 } { \text_purify:n { \text_expand:n { #2 } } } { #3 }
}
\int_new:N \l_hsmyers_xyz_comma_int
\int_new:N \l_hsmyers_xyz_qmark_int
\cs_new_protected:Nn \hsmyers_xyz_exy:nnnn
{
\hsmyers_xyz_count:nnN { , } { #3 } \l_hsmyers_xyz_comma_int
\hsmyers_xyz_count:nnN { ? } { #3 } \l_hsmyers_xyz_qmark_int
\int_compare:nTF { \l_hsmyers_xyz_qmark_int > 0 }
{
\addtocounter{wordCount}
{
\int_eval:n { \l_hsmyers_xyz_comma_int + \l_hsmyers_xyz_qmark_int }
}
\addtocounter{AllWord}
{
\int_eval:n { \l_hsmyers_xyz_comma_int + \l_hsmyers_xyz_qmark_int }
}
}{%
\addtocounter{wordCount}
{
\int_eval:n { \l_hsmyers_xyz_comma_int + \l_hsmyers_xyz_qmark_int + 1}
}
\addtocounter{AllWord}
{
\int_eval:n { \l_hsmyers_xyz_comma_int + \l_hsmyers_xyz_qmark_int + 1}
}
}
\textbf{#2}~#4,~``#1''
}
\cs_generate_variant:Nn \hsmyers_xyz_exy:nnnn { nne }
\cs_new_protected:Nn \hsmyers_xyz_count:nnN
{
\seq_set_split:Nnn \l_tmpa_seq { #1 } { #2 }
\int_set:Nn #3 { \seq_count:N \l_tmpa_seq - 1 }
}
\ExplSyntaxOff
\begin{document}
\test\par
\exy{one \Etc}{two \test \Etc{} s}{three \Etc{} s}
wordCount=\the\value{wordCount}
AllWord=\the\value{AllWord}
\exy{one \test}{two, three?}{three \test s}
wordCount=\the\value{wordCount}
AllWord=\the\value{AllWord}
\end{document}