
有沒有什麼方法可以計算 tikz 圖片中節點的高度並將一個長度除以另一個長度以獲得計數器並將其向上舍入?如果是的話,在使用不同類型的變數進行計算的主題之後我可以在哪裡閱讀?
這是一個例子:
\documentclass [a4paper] {article}
\usepackage{calc}
\usepackage{tikz,pgf}
\usetikzlibary{arrows}
%in this case i want to do a framebox with the parameter of 1 line's length in a tikz pictures
%because i dont know how could i get the heigth of the node i try to calculate it by divide the full length of the text (what i got with the command \settototalheight from the calc package) by the length of 1 line (this is a parameter) so i got the number of lines(this is a value not a length so i cannot use the \divide command because the type of the variable)
\newlength \widthofone \fullwidth \heightoneline \fullheight
\nemcounters \numberoflines
\newcommand {\altframe}[2] { %#1 the text #2 the width of the lines
\widthofone=#2pt %im not sure how to convert a length from a value but i try to input the 2nd parameter into a length variable
\settototalheight{\heightoneline}{qwe} %i get the height of one line by the calc package
\setwidth{\totalwidth}{#1} %i calculate the width of the text
%And now i would divide \fullwidth by \widthofone ,if i would know how to do it, to get \numberoflines
%I would multiply it by \height to get \fullheight
\begin{tikzpictures}
\node[text width=#2pt] at (0,0) {#1};%i write out the text
\draw[->,color=black] (\fullwidth/2,\fullheight/2) -- (0-\fullwidth/2,\fullheight/2); %i draw out the lines (i use height/2 becouse of the fact that the (0,0) coordinate is the middle of the picture)
\draw[->,color=black] (\fullwidth/2,0-\fullheight/2) -- (0-\fullwidth/2,0-\fullheight/2);
\draw[->,color=black] (\fullwidth/2,\fullheight/2) -- (\fullwidth/2,0-\fullheight/2);
\draw[->,color=black] (0-\fullwidth/2,\fullheight/2) -- (0-\fullwidth/2,0-\fullheight/2);
\end{tikzpictures}
}
\begin{document}
\altframe{i love this sample text}{100}
\end{document}
答案1
我不知道你要做什麼。但對於你的子問題:
計算tikz圖片中節點的高度
\makeatletter
\newcommand\getheightofnode[2]{%
\pgfextracty{#1}{\pgfpointanchor{#2}{north}}%
\pgfextracty{\pgf@ya}{\pgfpointanchor{#2}{south}}%
\addtolength{#1}{-\pgf@ya}}
\makeatother
將一個長度除以另一個長度
你可以\usetikzlibrary{math}
,只需寫
\tikzmath{
\numberoflines=\fullwidth/\widthofone;}
並將其四捨五入
\tikzmath{
\numberoflines=ceil(\fullwidth/\widthofone);}
然而,請注意
- 行數不能這樣計算。由於 TeX 傾向於在以下位置斷行適當的職位,行數通常較多。
- 「一條線的(總)高度」不是一個常數。例如
{x xx}
,{M MM}
、 、 和{j jj}
具有不同的高度。 - 更糟的是,「一條線的(總)高度在一個段落中' 與給你的不同
\settototalheight
。通常前者是\baselineskip
,但也可以更大。
所以我想下面的程式碼更接近你的方法
\documentclass{article}
\usepackage{calc,tikz}\usetikzlibrary{math}
\newlength\widthofone \newlength\fullwidth \newlength\heightoneline \newlength\fullheight
\makeatletter
\newcommand\getheightofnode[2]{%
\pgfextracty{#1}{\pgfpointanchor{#2}{north}}%
\pgfextracty{\pgf@ya}{\pgfpointanchor{#2}{south}}%
\addtolength{#1}{-\pgf@ya}}
\makeatother
\newcommand {\altframe}[2]{
\widthofone=#2
\heightoneline\baselineskip
\settowidth{\fullwidth}{#1}
\begin{tikzpicture}[->,color=black]
\node[text width=#2](baby)at(0,0){#1};
\getheightofnode\fullheight{baby}
\tikzmath{
\numberoflines=round(\fullheight/\heightoneline);}
\draw(\fullwidth/2,\fullheight/2)--(-\fullwidth/2,\fullheight/2);
\draw(\fullwidth/2,-\fullheight/2)--(-\fullwidth/2,-\fullheight/2);
\draw(\fullwidth/2,\fullheight/2)--(\fullwidth/2,-\fullheight/2);
\draw(-\fullwidth/2,\fullheight/2)--(-\fullwidth/2,-\fullheight/2);
\node[text width=5cm]at(0,-3){
widthofone =\the\widthofone \\
fullwidth =\the\fullwidth \\
heightoneline =\the\heightoneline \\
fullheight =\the\fullheight \\
numberoflines = \numberoflines};
\end{tikzpicture}}
\begin{document}
\altframe{i love this sample text}{50pt}
\end{document}