
又一天,又一個問題!這次我不明白為什麼填充後,tikz會留下這樣的空白
\documentclass[tikz,border=10pt]{standalone}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}[scale=0.7]
\coordinate (O) at (0,0);
\coordinate (I) at (12,0);
\coordinate (C1) at (4,0);
\coordinate (C2) at (7,0);
\draw ($ (O)+(-1,0) $) -- ($ (I)+(1,0) $);%asse ottico
\draw [very thick] (C1)++(75:-3) node (A1) {A1} arc (75:-75:-3) node (B1)
{B1};
\draw [very thick] (C2)++(75:3) node (A2) {A2} arc (75:-75:3) node (B2) {B2};
\begin{scope}
\clip (C1)++(75:-3) arc (75:-75:-3) -- (A2) -- (C2)++(75:3) arc (75:-75:3) --
(A1);
\filldraw [color=lightgray, opacity=0.6] (-10,-10) rectangle (20,10);
\end{scope}
\end{tikzpicture}
\end{document}
答案1
你甚至不需要clip
在這裡。問題是您++
在路徑中使用了增量。您可以對第一個座標執行此操作,但如果對其他座標執行此操作,則路徑會「跳躍」。然而,當你加載時calc
,你可以這樣做
\documentclass[tikz,border=10pt]{standalone}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}[scale=0.7]
\coordinate (O) at (0,0);
\coordinate (I) at (12,0);
\coordinate (C1) at (4,0);
\coordinate (C2) at (7,0);
\draw ($ (O)+(-1,0) $) -- ($ (I)+(1,0) $);%asse ottico
\draw [very thick] (C1)++(75:-3) node (A1) {A1} arc (75:-75:-3) node (B1)
{B1};
\draw [very thick] (C2)++(75:3) node (A2) {A2} arc (75:-75:3) node (B2) {B2};
\fill[color=lightgray, opacity=0.6](C1)++(75:-3) arc (75:-75:-3)
-- ($(C2)+(75:3)$) arc (75:-75:3) -- cycle ;
\end{tikzpicture}
\end{document}
但是,由於您已經有了命名節點,因此可以將其簡化為
\documentclass[tikz,border=10pt]{standalone}
\usetikzlibrary{calc,backgrounds}
\begin{document}
\begin{tikzpicture}[scale=0.7]
\coordinate (O) at (0,0);
\coordinate (I) at (12,0);
\coordinate (C1) at (4,0);
\coordinate (C2) at (7,0);
\draw ($ (O)+(-1,0) $) -- ($ (I)+(1,0) $);%asse ottico
\draw [very thick] (C1)++(75:-3) node (A1) {A1} arc (75:-75:-3) node (B1)
{B1};
\draw [very thick] (C2)++(75:3) node (A2) {A2} arc (75:-75:3) node (B2) {B2};
\begin{scope}[on background layer]
\fill[color=lightgray, opacity=0.6](A1.center) arc (75:-75:-3) --
(A2.center) arc (75:-75:3) -- cycle ;
\end{scope}
\end{tikzpicture}
\end{document}
這裡我也把填充放在了background layer
。