Bash 錯誤:「

Bash 錯誤:「

我試圖讓這個腳本正常運行,但我得到了./passmark.sh line 7: [y command not found

這是我的腳本

#!/bin/bash
# A simple script to ask a user for a pass mark and then display a grade
# the grade will be either an A, B, C, D or F
#
CONT=y
echo
while [$CONT = "y" ]
do
        echo -e "\"Please enter a pass mark: \c \""
        read MARK
        if [$MARK -ge "0" -a $MARK -lt "50"] ; then
                echo -e "\n \"F\" \n"
        elif [$MARK -ge "50" -a $MARK -lt "60"] ; then
                echo -e "\n \"D\" \n"
        elif [$MARK -ge "60" -a $MARK -lt "70"] ; then
                echo -e "\n \"C\" \n"
        elif [$MARK -ge "70" -a $MARK -lt "80"] ; then
                echo -e "\n \"B\" \n"
        elif [$MARK -ge "80" -a $MARK -lt "100"] ; then
                echo -e "\n \"A\" \n"
        else
                echo -e "\"Invalid input!!\n \""
        fi
        echo -e "\"Would you like to enter another pass mark? (y/n) \c \""
        read REPLY
        case "$REPLY" in
                n | N | no | No | NO ) CONT=n ;;
                *) ;;
        esac
echo
done 

答案1

您需要在[和周圍留有空格],例如

if [ "$MARK" -ge 0 -a "$MARK" -lt 50 ]; then

按照您編寫的方式,當$MARKis 時7,它會嘗試執行[7命令,而不是7作為參數傳遞給[命令([只是 的縮寫test)。

您還應該引用該變數。否則,如果使用者輸入空白行或多個單字,則測試表達式將無法正確解析。

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