首先,我不僅是 emacs 的新手,也是 UNIX 的新手。我試過寫:
#!/bin/bash
for i in {1..20}
do
j=(5*$i)+1
echo "$j"
done
結果:(5*1)+1(5*2)+1(5*3)+1(5*4)+1(5*5)+1(5*6)+1(5*7) + 1 (5*8)+1 (5*9)+1 (5*10)+1 (5*11)+1 (5*12)+1 (5*13)+1 (5*14)+ 1 (5*15)+1(5*16)+1(5*17)+1(5*18)+1(5*19)+1(5*20)+1
我實際上如何求和?
答案1
透過管道將其傳輸到 bc,很好的簡短簡單的答案;
echo "$j" | bc