私はこのコードに遭遇しました。これは非常に役に立ちますが、コードを実行するとすべてのノードに関してエラーが発生します。(例えば、図形に名前が付けられていないA-2-1)ノードのラベル付け方法は他のコードでは問題なく機能するので、何が問題なのかわかりません。ここで何が問題なのか、何か考えはありますか?
% Author : Alain Matthes
% Source : http://altermundus.com/pages/examples.html
\documentclass[]{article}
\usepackage[utf8]{inputenc}
\usepackage[upright]{fourier}
\usepackage{tikz}
\usetikzlibrary{matrix,arrows,decorations.pathmorphing}
\begin{document}
% l' unite
\newcommand{\myunit}{1 cm}
\tikzset{
node style sp/.style={draw,circle,minimum size=\myunit},
node style ge/.style={circle,minimum size=\myunit},
arrow style mul/.style={draw,sloped,midway,fill=white},
arrow style plus/.style={midway,sloped,fill=white},
}
\begin{tikzpicture}[>=latex]
% les matrices
\matrix(A)[matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )] at (0,0)
{%
a_{11} & a_{12} & \ldots & a_{1p} \\
\node[node style sp] {a_{21}};%
& \node[node style sp] {a_{22}};%
& \ldots%
& \node[node style sp] {a_{2p}}; \\
\vdots & \vdots & \ddots & \vdots \\
a_{n1} & a_{n2} & \ldots & a_{np} \\
};
\node [draw,below=10pt] at (A.south)
{ $A$ : \textcolor{red}{$n$ rows} $p$ columns};
\matrix (B) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter =)] at (6*\myunit,6*\myunit)
{%
b_{11} & \node[node style sp] {b_{12}};%
& \ldots & b_{1q} \\
b_{21} & \node[node style sp] {b_{22}};%
& \ldots & b_{2q} \\
\vdots & \vdots & \ddots & \vdots \\
b_{p1} & \node[node style sp] {b_{p2}};%
& \ldots & b_{pq} \\
};
\node [draw,above=10pt] at (B.north)
{ $B$ : $p$ rows \textcolor{red}{$q$ columns}};
% matrice résultat
\matrix (C) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )] at (6*\myunit,0)
{%
c_{11} & c_{12} & \ldots & c_{1q} \\
c_{21} & \node[node style sp,red] {c_{22}};%
& \ldots & c_{2q} \\
\vdots & \vdots & \ddots & \vdots \\
c_{n1} & c_{n2} & \ldots & c_{nq} \\
};
% les fleches
\draw[blue] (A-2-1.north) -- (C-2-2.north);
\draw[blue] (A-2-1.south) -- (C-2-2.south);
\draw[blue] (B-1-2.west) -- (C-2-2.west);
\draw[blue] (B-1-2.east) -- (C-2-2.east);
\draw[<->,red](A-2-1) to[in=180,out=90]
node[arrow style mul] (x) {$a_{21}\times b_{12}$} (B-1-2);
\draw[<->,red](A-2-2) to[in=180,out=90]
node[arrow style mul] (y) {$a_{22}\times b_{22}$} (B-2-2);
\draw[<->,red](A-2-4) to[in=180,out=90]
node[arrow style mul] (z) {$a_{2p}\times b_{p2}$} (B-4-2);
\draw[red,->] (x) to node[arrow style plus] {$+$} (y)%
to node[arrow style plus] {$+\raisebox{.5ex}{\ldots}+$} (z)%
to (C-2-2.north west);
\node [draw,below=10pt] at (C.south)
{$ C=A\times B$ : \textcolor{red}{$n$ rows} \textcolor{red}{$q$ columns}};
\end{tikzpicture}
\begin{tikzpicture}[>=latex]
% unit
% defintion of matrices
\matrix (A) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )] at (0,0)
{%
a_{11} &\ldots & a_{1k} & \ldots & a_{1p} \\
\vdots & \ddots & \vdots & \vdots & \vdots \\
\node[node style sp] {a_{i1}};& \ldots%
& \node[node style sp] {a_{ik}};%
& \ldots%
& \node[node style sp] {a_{ip}}; \\
\vdots & \vdots& \vdots & \ddots & \vdots \\
a_{n1}& \ldots & a_{nk} & \ldots & a_{np} \\
};
\node [draw,below] at (A.south) { $A$ : \textcolor{red}{$n$ rows} $p$ columns};
\matrix (B) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter =)] at (7*\myunit,7*\myunit)
{%
b_{11} & \ldots& \node[node style sp] {b_{1j}};%
& \ldots & b_{1q} \\
\vdots& \ddots & \vdots & \vdots & \vdots \\
b_{k1} & \ldots& \node[node style sp] {b_{kj}};%
& \ldots & b_{kq} \\
\vdots& \vdots & \vdots & \ddots & \vdots \\
b_{p1} & \ldots& \node[node style sp] {b_{pj}};%
& \ldots & b_{pq} \\
};
\node [draw,above] at (B.north) { $B$ : $p$ rows \textcolor{red}{$q$ columns}};
% matrice resultat
\matrix (C) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )] at (7*\myunit,0)
{%
c_{11} & \ldots& c_{1j} & \ldots & c_{1q} \\
\vdots& \ddots & \vdots & \vdots & \vdots \\
c_{i1}& \ldots & \node[node style sp,red] {c_{ij}};%
& \ldots & c_{iq} \\
\vdots& \vdots & \vdots & \ddots & \vdots \\
c_{n1}& \ldots & c_{nk} & \ldots & c_{nq} \\
};
\node [draw,below] at (C.south)
{$ C=A\times B$ : \textcolor{red}{$n$ rows} \textcolor{red}{$q$ columns}};
% arrows
\draw[blue] (A-3-1.north) -- (C-3-3.north);
\draw[blue] (A-3-1.south) -- (C-3-3.south);
\draw[blue] (B-1-3.west) -- (C-3-3.west);
\draw[blue] (B-1-3.east) -- (C-3-3.east);
\draw[<->,red](A-3-1) to[in=180,out=90]
node[arrow style mul] (x) {$a_{i1}\times b_{1j}$} (B-1-3);
\draw[<->,red](A-3-3) to[in=180,out=90]
node[arrow style mul] (y) {$a_{ik}\times b_{kj}$}(B-3-3);
\draw[<->,red](A-3-5) to[in=180,out=90]
node[arrow style mul] (z) {$a_{ip}\times b_{pj}$}(B-5-3);
\draw[red,->] (x) to node[arrow style plus] {$+\raisebox{.5ex}{\ldots}+$} (y)%
to node[arrow style plus] {$+\raisebox{.5ex}{\ldots}+$} (z);
%
% to (C-3-3.north west);
\draw[->,red,decorate,decoration=zigzag] (z) -- (C-3-3.north west);
\end{tikzpicture}
\end{document}
答え1
代わりに次のように\node[node style sp] {a_{21}};書きます|[node style sp]| {a_{21}}:
\documentclass[]{article}
\usepackage[utf8]{inputenc}
\usepackage[upright]{fourier}
\usepackage{tikz}
\usetikzlibrary{arrows,matrix,decorations.pathmorphing}
\begin{document}
% l' unite
\newcommand{\myunit}{1 cm}
\tikzset{
node style sp/.style={draw,circle,minimum size=\myunit},
node style ge/.style={circle,minimum size=\myunit},
arrow style mul/.style={draw,sloped,midway,fill=white},
arrow style plus/.style={midway,sloped,fill=white},
}
\begin{tikzpicture}[>=latex]
% les matrices
\matrix (A) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )]
{%
a_{11} & a_{12} & \ldots & a_{1p} \\
|[node style sp]| {a_{21}}%
& |[node style sp]| {a_{22}}%
& \ldots%
& |[node style sp]| {a_{2p}} \\
\vdots & \vdots & \ddots & \vdots \\
a_{n1} & a_{n2} & \ldots & a_{np} \\
};
\node [draw,below=10pt] at (A.south)
{ $A$ : \textcolor{red}{$n$ rows} $p$ columns};
\matrix (B) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter =)] at (6*\myunit,6*\myunit)
{%
b_{11} & |[node style sp]| {b_{12}}%
& \ldots & b_{1q} \\
b_{21} & |[node style sp]| {b_{22}}%
& \ldots & b_{2q} \\
\vdots & \vdots & \ddots & \vdots \\
b_{p1} & |[node style sp]| {b_{p2}}%
& \ldots & b_{pq} \\
};
\node [draw,above=10pt] at (B.north)
{ $B$ : $p$ rows \textcolor{red}{$q$ columns}};
% matrice resultat
\matrix (C) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )] at (6*\myunit,0)
{%
c_{11} & c_{12} & \ldots & c_{1q} \\
c_{21} & |[node style sp,red]| {c_{22}}%
& \ldots & c_{2q} \\
\vdots & \vdots & \ddots & \vdots \\
c_{n1} & c_{n2} & \ldots & c_{nq} \\
};
% les fleches
\draw[blue] (A-2-1.north) -- (C-2-2.north);
\draw[blue] (A-2-1.south) -- (C-2-2.south);
\draw[blue] (B-1-2.west) -- (C-2-2.west);
\draw[blue] (B-1-2.east) -- (C-2-2.east);
\draw[<->,red](A-2-1) to[in=180,out=90]
node[arrow style mul] (x) {$a_{21}\times b_{12}$} (B-1-2);
\draw[<->,red](A-2-2) to[in=180,out=90]
node[arrow style mul] (y) {$a_{22}\times b_{22}$} (B-2-2);
\draw[<->,red](A-2-4) to[in=180,out=90]
node[arrow style mul] (z) {$a_{2p}\times b_{p2}$} (B-4-2);
\draw[red,->] (x) to node[arrow style plus] {$+$} (y)%
to node[arrow style plus] {$+\raisebox{.5ex}{\ldots}+$} (z)%
to (C-2-2.north west);
\node [draw,below=10pt] at (C.south)
{$ C=A\times B$ : \textcolor{red}{$n$ rows} \textcolor{red}{$q$ columns}};
\end{tikzpicture}
\end{document}
答え2
マトリックスは、すでに
\matrix(A)[matrix of math nodes,%
したがって、以下の2番目のコマンドは最初のノード内にノードをネストしますが、これは不正です。
\node[node style sp] {a_{21}};%
したがって、これを実行する場合は、2番目の/nestedノードを、メインマトリックス(A)のA-2-1ではなく、別のエイリアスで呼び出す必要があります。
2番目のネストされたノードには別の名前（A-2-1）を付けました。同様に、行列（C）の2番目のネストされたノード（C-2-2）には別の名前が付けられています。
これで、これら2つのノード間で描画コマンドを使用するとエラーは発生しません。
\draw[blue] (A-2-1.north) -- (C-2-2.north);
結果は以下のようになります。
以下のリンクで説明されているようにエイリアスを使用することもできます ==