
Considere el MWE:
\documentclass{article}
\usepackage{tikz}
\usepackage{graphicx}
% % COMPILED WITH PDFLATEX
\newif\ifdeveloppath
\tikzset{/tikz/develop clipping path/.is if=developpath,
/tikz/develop clipping path=true}
\newcommand{\clippicture}[2]{
\begin{tikzpicture}
\ifdeveloppath
\node[anchor=south west,inner sep=0] (image) at (0,0) {\includegraphics[width=1.0\linewidth,keepaspectratio]{example-image-a}};
\else
\node[anchor=south west,inner sep=0] (image) at (0,0) {\phantom{\includegraphics[width=1.0\linewidth,keepaspectratio]{example-image-a}}};
\fi
\pgfresetboundingbox
\begin{scope}[x={(image.south east)},y={(image.north west)}]
% Draw grid
\ifdeveloppath
\draw[help lines,xstep=.02,ystep=.02] (0,0) grid (1,1);
\foreach \x in {0,1,...,9} { \node [anchor=north] at (\x/10,0) {0.\x}; }
\foreach \y in {0,1,...,9} { \node [anchor=east] at (0,\y/10) {0.\y}; }
\draw[red, ultra thick] #2 -- cycle;
\else
% Use the path to clip
\path[clip] #2 -- cycle;
\node[anchor=south west,inner sep=0pt] {\includegraphics[width=1.0\linewidth,keepaspectratio]{example-image-a}};
\fi
\end{scope}
\end{tikzpicture}
}
\begin{document}
\thispagestyle{empty}
\clippicture{[width=1.0\textwidth]{some-image}}{(0.359,0.268) -- (0.48,0.73) -- (0.52,0.73) -- (0.64,0.27) -- (0.60,0.27) -- (0.562,0.403) -- (0.43,.403) -- (0.395, 0.268) -- (0.359,0.268)}
\newpage
\thispagestyle{empty}
\tikzset{develop clipping path=false}
\begin{center}
\clippicture{[width=1.0\textwidth]{some-image}}{(0.359,0.268) -- (0.48,0.73) -- (0.52,0.73) -- (0.64,0.27) -- (0.60,0.27) -- (0.562,0.403) -- (0.43,.403) -- (0.395, 0.268) -- (0.359,0.268)}
\end{center}
\end{document}
con la salida:
PREGUNTA: Mi trazado de recorte es un circuito cerrado; y entonces, la producción es la porción exterior del capital.A. ¿Cómo podría completar la extracción de la carta?Arecortando también la parte interior apropiada de la cartaA?
Gracias.
Respuesta1
Agregue el triángulo interior de la "A" en el sentido contrario a las agujas del reloj (usando la "regla distinta de cero") a su camino, haciéndolo:
(0.359,0.268) -- (0.48,0.73) -- (0.52,0.73) -- (0.64,0.27) -- (0.60,0.27) -- (0.562,0.403) -- (0.43,.403) -- (0.395, 0.268) -- (0.359,0.268) (0.440,0.438) -- (0.555,0.438) -- (0.498,0.675) -- (0.44,0.44)
Al hacer un camino cerrado, es mejor utilizar cycle
en lugar de repetir la primera coordenada. Esto hace el camino:
(0.359,0.268) -- (0.48,0.73) -- (0.52,0.73) -- (0.64,0.27) -- (0.60,0.27) -- (0.562,0.403) -- (0.43,.403) -- (0.395, 0.268) -- cycle (0.440,0.438) -- (0.555,0.438) -- (0.498,0.675) -- cycle