有什麼方法可以格式化 grep 命令的輸出以很好地對齊列嗎?例如:
4TO/struct-2222332/coord-2222332.out: FINAL HEAT OF FORMATION = -299.61496 KCAL/MOL = -1253.58899 KJ/MOL
2E/struct-1212123/coord-1212123.out: FINAL HEAT OF FORMATION = -299.61496 KCAL/MOL = -1253.58901 KJ/MOL
OT4/struct-2222121/coord-2222121.out: FINAL HEAT OF FORMATION = -299.61497 KCAL/MOL = -1253.58904 KJ/MOL
E3/struct-1312322/coord-1312322.out: FINAL HEAT OF FORMATION = -299.61497 KCAL/MOL = -1253.58903 KJ/MOL
我想為第一列分配 40 個空格,並從左對齊。同樣,根據每列的預期最大大小對其他列執行相同的操作。
答案1
您可以使用該column
命令(如果您使用的是 Linux)將資料格式化為製表符分隔的列。不過,我認為您無法為第一列和其他列指定不同的列寬。
bash-[24]$ column -t /tmp/output
4TO/struct-2222332/coord-2222332.out: FINAL HEAT OF FORMATION = -299.61496 KCAL/MOL = -1253.58899 KJ/MOL
2E/struct-1212123/coord-1212123.out: FINAL HEAT OF FORMATION = -299.61496 KCAL/MOL = -1253.58901 KJ/MOL
OT4/struct-2222121/coord-2222121.out: FINAL HEAT OF FORMATION = -299.61497 KCAL/MOL = -1253.58904 KJ/MOL
E3/struct-1312322/coord-1312322.out: FINAL HEAT OF FORMATION = -299.61497 KCAL/MOL = -1253.58903 KJ/MOL
您的另一個選擇是解析文件、拆分欄位並使用 和 自行處理awk
列printf()
。
bash-[54]$ awk '{printf "%-40s",$1 ; $1=""; printf "%-s\n",$0}' /tmp/output
4TO/struct-2222332/coord-2222332.out: FINAL HEAT OF FORMATION = -299.61496 KCAL/MOL = -1253.58899 KJ/MOL
2E/struct-1212123/coord-1212123.out: FINAL HEAT OF FORMATION = -299.61496 KCAL/MOL = -1253.58901 KJ/MOL
OT4/struct-2222121/coord-2222121.out: FINAL HEAT OF FORMATION = -299.61497 KCAL/MOL = -1253.58904 KJ/MOL
E3/struct-1312322/coord-1312322.out: FINAL HEAT OF FORMATION = -299.61497 KCAL/MOL = -1253.58903 KJ/MOL