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jq + 更新json檔案並依ID號碼附加名稱

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jq + 更新json檔案並依ID號碼附加名稱

我們要根據以下規則編輯json文件

我們需要產生 name car0X_hyb.com -undermazda 字串（而 X 是 ID 號碼）

我們需要更新 Linux 機器上的 json 文件

例子 - ID=1

那麼 json 將是

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

ID=4, 那麼 json 將是

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

ID=6, 那麼 json 將是

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com",
    "car06_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

ID=10, 那麼 json 將是

{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com",
    "car06_hyb.com",
    "car07_hyb.com",
    "car08_hyb.com",
    "car09_hyb.com",
    "car10_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

答案1

似乎沒有一種不醜陋的方法來對 ID 進行零填充，但是考慮到

$ jq '.' file.json
{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "foo.bar"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

然後例如對於ID= 11：

$ jq --arg ID 11 '
    .mazda |= [range(1;($ID | tonumber)+1) as $ID | if $ID < 10 then "car0\($ID)_hyb.com" else "car\($ID)_hyb.com" end]
' file.json
{
  "toyota": [
    "car1.com"
  ],
  "mazda": [
    "car01_hyb.com",
    "car02_hyb.com",
    "car03_hyb.com",
    "car04_hyb.com",
    "car05_hyb.com",
    "car06_hyb.com",
    "car07_hyb.com",
    "car08_hyb.com",
    "car09_hyb.com",
    "car10_hyb.com",
    "car11_hyb.com"
  ],
  "ford": [
    "car01_eng.com"
  ]
}

或者（也許這更好）在 shell 中生成並格式化完整的字串元素，並將其作為argjson:

jq --argjson IDS '['"$(seq -s, -f'"car%02.0f_hyb.com"' 11)"']' '
  .mazda |= $IDS
' file.json

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