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\documentclass[border=2mm, tikz]{standalone}
\usetikzlibrary{shapes.geometric}
\begin{document}
\begin{tikzpicture}[
x=7.5mm,y=4.34mm,
box/.style={
regular polygon,
regular polygon sides=6,
minimum size=10mm,
inner sep=0mm, outer sep=0mm,
draw}
]
\node [box] (innerbox) {};
\foreach \x [evaluate=\x as \y using {int(ifthenelse(\x+2>6,\x-4,\x+2))}] in {1,...,6}
\node [box,anchor=corner \y] at (innerbox.corner \x) {};
\end{tikzpicture}
\end{document}
答案1
您的程式碼無法按原樣編譯。請在發布範例之前檢查程式碼是否已編譯,除非問題在於未編譯。在這種情況下,請確保它產生您所詢問的錯誤。
該代碼可能不適合您。它不可能產生沒有錯誤的輸出,因為它在各種隨機奇怪的地方包含段落中斷,這會給出一個又一個錯誤。
至於問題,為什麼不能在迴圈中使用第二個變數?
\documentclass[border=5pt, tikz]{standalone}
\usetikzlibrary{shapes.geometric}
\begin{document}
\begin{tikzpicture}[
x=7.5mm,y=4.34mm,
box/.style={
regular polygon,
regular polygon sides=6,
minimum size=10mm,
inner sep=0mm, outer sep=0mm,
draw}
]
\node [box] (innerbox) {g};
\foreach \i/\j [evaluate=\i as \k using {int(ifthenelse(\i+2>6,\i-4,\i+2))}] in {1/a,2/b,3/c,4/d,5/e,6/f}
\node [box,anchor=corner \k] at (innerbox.corner \i) {\j};
\end{tikzpicture}
\end{document}
編輯
您也可以簡化事情,以便只需要指定節點的名稱。例如:
\documentclass[border=5pt, tikz]{standalone}
\usetikzlibrary{shapes.geometric}
\begin{document}
\begin{tikzpicture}[
box/.style={
regular polygon,
regular polygon sides=6,
minimum size=10mm,
inner sep=0mm,
outer sep=0mm,
inner color=orange!75!red!50!yellow,
outer color=orange!75!red!75!yellow,
draw=orange,
text=red,
},
]
\node [box] (innerbox) {7};
\foreach \i [count=\k from 0, evaluate=\k as \j using {int(60*\k+30)}, evaluate=\j as \l using {(int(\j+180))} ] in {10,6,4,3,1,9}
\node (h\k) [box, anchor=\l] at (innerbox.\j) {\i};
\end{tikzpicture}
\end{document}
產生以下結果(對於蜜蜂):