
我正在嘗試添加穿過點 (1000,-8.5) 和 (10000,-27.79) 的線。這是我目前擁有的乳膠。
\begin{figure}[h!]
\begin{center}
\begin{tikzpicture}
\begin{axis}[
xmode=log,
xlabel={Frequency (Hz)},
ylabel={Gain (db)},
xmin=0, xmax=20000,
ymin=-30, ymax=10,
xtick={0,100,1000,10000},
ytick={10,0,-10,-20,-30},
legend pos=north west,
ymajorgrids=true,
grid style=dashed,
]
\addplot[
color=blue,
mark=square,
only marks,
]
coordinates {
(100,-0.18)(1000,-8.5)(2000,-14.15)(4000,-19.83)(10000,-27.79)
};
% add plot of equation going through points (1000,-8.5) and (10000,-27.79) here
\end{axis}
\end{tikzpicture}
\end{center}
\end{figure}
我猜測通過這兩個點的所有方程式都沒有正確顯示在圖上,因為對數刻度。我嘗試過 49.37-19.29*x 但不起作用。在計算連接兩點的線之前應用 log(x) 可得出方程式。如何得到一條穿過這些點的線?
答案1
怎麼樣
\documentclass[tikz,border=3.14mm]{standalone}
\usepackage{pgfplots}
\pgfplotsset{compat=1.16}
\begin{document}
\begin{tikzpicture}
\begin{axis}[
xmode=log,
xlabel={Frequency (Hz)},
ylabel={Gain (db)},
xmin=0, xmax=20000,
ymin=-30, ymax=10,
xtick={0,100,1000,10000},
ytick={10,0,-10,-20,-30},
legend pos=north west,
ymajorgrids=true,
grid style=dashed,
legend pos=north east
]
\addplot[
color=blue,
mark=square,
only marks,
]
coordinates {
(100,-0.18)(1000,-8.5)(2000,-14.15)(4000,-19.83)(10000,-27.79)
};
\addlegendentry{data}
\addplot[color=orange,no marks] coordinates {(1000,-8.5) (10000,-27.79)};
\addlegendentry{fit}
\end{axis}
\end{tikzpicture}
\end{document}