我正在使用解決方案形式透過數學節點的 TiKZ 矩陣模擬 amsmath 矩陣的障礙tikz
matrix
以 a 的風格創建bmatrix
.
我想在最後一行後留一點額外的空間,並認為使用\\[1.5ex]
應該可以完成這項工作:
\matrix (m) {
1 & 4 \\
7 & 10 \\
13 & 16 \\[1.5ex]% <--- This seems to have no effect.
};
但這似乎沒有任何效果。對任何行使用此可選參數,但最後一行似乎有效。
該bmatrix
版本的行為符合預期。
相關問題
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tikz
垂直間距的問題,而是類似的問題。
代碼:
\documentclass{article}
\usepackage{mathtools}% for amsmath {bmatrix}
\usepackage{tikz}
\usetikzlibrary{matrix}
%% https://tex.stackexchange.com/questions/26866/obstacles-to-simulating-an-amsmath-matrix-by-a-tikz-matrix-of-math-nodes
\newlength\mtxrowsep \setlength\mtxrowsep{1.5ex}
\newlength\mtxcolsep \setlength\mtxcolsep{2\arraycolsep}
\tikzset{
ams/.style={
baseline=-.7ex,
every delimiter/.style={yshift=-1pt},
every left delimiter/.style={xshift=2pt},
every right delimiter/.style={xshift=-2pt},
every node/.style={inner sep=0pt},
},
ams matrix/.style={
inner sep=1pt,
column sep=\mtxcolsep,
row sep=\mtxrowsep,
% Following is also commented at https://tex.stackexchange.com/questions/26866
%ampersand replacement=\&,
matrix of math nodes,
},
bmatrix/.style={
ams,
every matrix/.style={
ams matrix,
left delimiter={[},
right delimiter={]},
}
},
Bmatrix/.style={
ams,
every matrix/.style={
ams matrix,
left delimiter={\lbrace},
right delimiter={\rbrace},
}
},
pmatrix/.style={
ams,
every matrix/.style={
ams matrix,
left delimiter={(},
right delimiter={)},
}
},
vmatrix/.style={
ams,
every matrix/.style={
ams matrix,
left delimiter={|},
right delimiter={|},
}
},
Vmatrix/.style={
ams,
every matrix/.style={
ams matrix,
left delimiter={\|},
right delimiter={\|},
}
},
}
%% This does not seem to be necessary here
%\let\matamp=&
%
%\catcode`\&=13
%\makeatletter
%\def&{\iftikz@is@matrix
% \pgfmatrixnextcell
% \else
% \matamp
% \fi}
%\makeatother
\begin{document}
\hspace*{0.2em}
\begin{tikzpicture}[bmatrix]
\matrix (m) {
1 & 4 \\
7 & 10 \\
13 & 16 \\[1.5ex]% <--- This seems to have no effect.
};
\end{tikzpicture}
%% ----------------
\hspace*{0.3em}
$\begin{bmatrix}
\smash{1} & \smash{4} \\
7 & 10 \\
13 & 16 \\[1.5ex]
\end{bmatrix}$
tikz matrix \hspace*{0.6em} bmatrix
\end{document}
臨時附錄:
我嘗試使用 Qrrbrbirlbel 的解決方案,但遇到了一個問題:節點的座標不再是tikz
它們認為的位置。使用答案中提供的前導碼和以下程式碼,似乎節點(例如m-1-1.north west
)發生了移位:
\newcommand{\FillMatrix}{%
\fill [rounded corners=3pt, fill opacity=.35, fill=green!80]
([shift={(0pt, 2pt)}]m-1-1.north west)
-- ([shift={(0pt,-2pt)}]m-2-1.south west)
-- ([shift={(2pt,-2pt)}]m-2-2.south east)
-- ([shift={(2pt, 0pt)}]m-2-2.north east)
-- cycle;
}%
\begin{document}
\hspace*{0.2em}
\begin{tikzpicture}[bmatrix]
\matrix (m) {
1 & 4 \\
7 & 10 \\
13 & 16 \\[-2pt]
};
\FillMatrix
\end{tikzpicture}
%% ----------------
\hspace*{0.3em}
\begin{tikzpicture}[bmatrix, matrix bottom crcr]
\matrix (m) {
1 & 4 \\
7 & 10 \\
13 & 16 \\[-2pt]
};
\FillMatrix
\end{tikzpicture}
\hspace*{0.6em} default \hspace*{0.6em} matrix bottom crcr
\end{document}
答案1
最後一個[<vspace>]
沒有效果,因為 PGF 根本不執行與普通\\
.它會評估並保存它,以便我們可以在下面的補丁中使用它。完成後,它會檢查後面是否有}
(= \egroup
),這表示矩陣內容的結尾。
如果沒有,在 a 之後,\cr
它將\vskip
根據行的大小以及是否使用了between origins
or來執行一些 s between borders
,然後繼續處理下一行。
如果是,則僅結束行 ( \cr
) 並結束矩陣 ( \pgf@end@matrix
)。不過,我們可以按照相同的\vskip
流程進行修補。
(PGF 矩陣是透過\halign
它實現的,這就是您在程式碼中看到\cr
s 和s 的原因。)\noalign
為了安全起見,我將為此添加一個切換開關matrix bottom crcr
,以便您可以在其他矩陣無法正常工作時禁用它。
程式碼
\documentclass{article}
\usepackage{mathtools}% for amsmath {bmatrix}
\usepackage{tikz}
\usetikzlibrary{matrix}
%% https://tex.stackexchange.com/questions/26866/obstacles-to-simulating-an-amsmath-matrix-by-a-tikz-matrix-of-math-nodes
\newlength\mtxrowsep \setlength\mtxrowsep{1.5ex}
\newlength\mtxcolsep \setlength\mtxcolsep{2\arraycolsep}
\tikzset{
ams/.style={
baseline=-.7ex,
every delimiter/.style={yshift=-1pt},
every left delimiter/.style={xshift=2pt},
every right delimiter/.style={xshift=-2pt},
every node/.style={inner sep=0pt},
},
ams matrix/.style={
inner sep=1pt,
column sep=\mtxcolsep,
row sep=\mtxrowsep,
matrix of math nodes,
},
create ams matrix/.style n args={3}{#1matrix/.style={
ams, every matrix/.style={
ams matrix, left delimiter={#2}, right delimiter={#3}}}},
create ams matrix/.list={b[], B\lbrace\rbrace, p(), v||, V\|\|},
}
\makeatletter
\let\pgf@matrix@finish@line@orig\pgf@matrix@finish@line
\tikzset{
matrix bottom crcr/.is choice, matrix bottom crcr/.default=enabled,
matrix bottom crcr/enabled/.code=
\let\pgf@matrix@finish@line\qrr@pgf@matrix@finish@line
\def\pgf@matrix@last@line@y{\ifpgf@matrix@noendrow@skip0pt\else\the\pgf@y\fi},
matrix bottom crcr/disabled/.code=
\let\pgf@matrix@finish@line\pgf@matrix@finish@line@orig
\def\pgf@matrix@last@line@y{0pt}}
\def\qrr@pgf@matrix@finish@line{%
\global\pgf@y=\pgf@y%
\pgf@ya=-\pgf@y%
\global\advance\pgf@ya by\csname pgf@matrix@miny\the\pgfmatrixcurrentrow\endcsname%
\expandafter\xdef\csname pgf@matrix@miny\the\pgfmatrixcurrentrow\endcsname{\the\pgf@ya}%
\pgfutil@ifnextchar\egroup{\pgf@matrix@eom@found}{\pgf@matrix@no@eom@found}% Qrr: change
}%
\def\pgf@matrix@eom@found{% Qrr: overwrite (unused before)
\cr
\unless\ifpgf@matrix@noendrow@skip
\noalign{%
\vskip\pgf@y
\ifpgf@matrix@fixed % Qrr: “between borders”
\vskip\csname pgf@matrix@miny\the\pgfmatrixcurrentrow\endcsname% unskip
\vskip\pgf@y
\pgf@y=-\pgf@y
\expandafter\xdef\csname pgf@matrix@miny\the\pgfmatrixcurrentrow\endcsname{\the\pgf@y}%
\fi
}%
\fi
\pgf@end@matrix
}%
\usepackage{etoolbox}
\patchcmd\pgf@matrix@compute@origin{0pt}{\pgf@matrix@last@line@y}{}{\PatchFailed}
\def\pgf@matrix@last@line@y{0pt}
\newif\ifpgf@matrix@noendrow@skip
\patchcmd\pgfmatrixendrow
{\pgfutil@ifnextchar[{\pgfmatrixendrow@skip}{\pgf@matrix@finish@line}}
{\pgfutil@ifnextchar[{\global\pgf@matrix@noendrow@skipfalse\pgfmatrixendrow@skip}
{\global\pgf@matrix@noendrow@skiptrue\pgf@matrix@finish@line}}
{}{\PatchFailed}
\makeatother
\newcommand{\FillMatrix}{%
\fill [rounded corners=3pt, fill opacity=.35, fill=green!80]
([shift={(0pt, 2pt)}]m-1-1.north west)
-- ([shift={(0pt,-2pt)}]m-2-1.south west)
-- ([shift={(2pt,-2pt)}]m-2-2.south east)
-- ([shift={(2pt, 0pt)}]m-2-2.north east)
-- cycle;
}%
\newcommand*\AMSMATH[1]{$\begin{bmatrix}\smash{1} & \smash{4} \\ 7 & 10 \\ 13 & 16 \\#1\end{bmatrix}$}
\begin{document}
no patch, \verb|\\|:\par
\begin{tikzpicture}[bmatrix]
\matrix (m) {
1 & 4 \\
7 & 10 \\
13 & 16 \\
};
\FillMatrix
\end{tikzpicture}\AMSMATH{}\medskip
no patch, \verb|\\[1.5ex]|:\par
\begin{tikzpicture}[bmatrix]
\matrix (m) [row sep=0pt]{
1 & 4 \\
7 & 10 \\
13 & 16 \\[1.5ex]
};
\FillMatrix
\end{tikzpicture}\AMSMATH{[1.5ex]}\bigskip
patch, \verb|\\|:\par
\begin{tikzpicture}[bmatrix, matrix bottom crcr]
\matrix (m) {
1 & 4 \\
7 & 10 \\
13 & 16 \\
};
\FillMatrix
\end{tikzpicture}\AMSMATH{}\medskip
patch, \verb|\\[1.5ex]| (row sep + arg inserted) (\AmS: \verb|[3.0ex]|):\par
\begin{tikzpicture}[bmatrix, matrix bottom crcr]
\matrix (m) [row sep=0pt]{
1 & 4 \\
7 & 10 \\
13 & 16 \\[1.5ex]
};
\FillMatrix
\end{tikzpicture}\AMSMATH{[3ex]}\medskip
patch, \verb|\\[-\pgfmatrixrowsep]| (row sep compensated):\par
\begin{tikzpicture}[bmatrix, matrix bottom crcr]
\matrix (m) [row sep=0pt]{
1 & 4 \\
7 & 10 \\
13 & 16 \\[-\pgfmatrixrowsep]
};
\FillMatrix
\end{tikzpicture}
\end{document}